15x^2+44x+13=0

Solution for 15x^2+44x+13=0 equation:

15x^2+44x+13=0

a = 15; b = 44; c = +13;
Δ = b2-4ac
Δ = 442-4·15·13
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-34}{2*15}=\frac{-78}{30}
=-2+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+34}{2*15}=\frac{-10}{30}
=-1/3
$